-46(-3)=7x^2-4

Solution for -46(-3)=7x^2-4 equation:

-46(-3)=7x^2-4

We move all terms to the left:

-46(-3)-(7x^2-4)=0

We add all the numbers together, and all the variables

-(7x^2-4)+138=0

We get rid of parentheses

-7x^2+4+138=0

We add all the numbers together, and all the variables

-7x^2+142=0

a = -7; b = 0; c = +142;
Δ = b2-4ac
Δ = 02-4·(-7)·142
Δ = 3976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3976}=\sqrt{4*994}=\sqrt{4}*\sqrt{994}=2\sqrt{994}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{994}}{2*-7}=\frac{0-2\sqrt{994}}{-14}
=-\frac{2\sqrt{994}}{-14}
=-\frac{\sqrt{994}}{-7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{994}}{2*-7}=\frac{0+2\sqrt{994}}{-14}
=\frac{2\sqrt{994}}{-14}
=\frac{\sqrt{994}}{-7}
$